Answer:
Step-by-step explanation:
Given that an inspector inspects large truckloads of potatoes to determine the proportion p in the shipment with major defects prior to using the potatoes to make potato chips.
[tex]H 0 : p = 0.10 , \\H a : p < 0.10[/tex]
n =100
SE = [tex]\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.1*0.9}{100} } \\=0.03[/tex]
Sample P = 6 out of 100 = 0.06
p difference = -0.04
p value = 0.484
Since p value >0.05 we accept null hypothesis