Answer:
[tex]D=\sqrt{10}\approx 3.16[/tex] units.
Step-by-step explanation:
We are asked to find the distance between [tex](-6,8)[/tex] and [tex](-3,9)[/tex].
We will use distance formula to solve our given problem. [tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Let point [tex](-6,8)=(x_1,y_1)[/tex] and [tex](-3,9)=(x_2,y_2)[/tex].
[tex]D=\sqrt{(-3-(-6))^2+(9-8)^2}[/tex]
[tex]D=\sqrt{(-3+6)^2+(1)^2}[/tex]
[tex]D=\sqrt{(3)^2+(1)^2}[/tex]
[tex]D=\sqrt{9+1}[/tex]
[tex]D=\sqrt{10}[/tex]
[tex]D\approx 3.16[/tex]
Therefore, the distance between our given points is [tex]D=\sqrt{10}\approx 3.16[/tex] units.
The distance between the two points is √10
The formula for calculating the distance between two points is expressed as:
[tex]D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
Given the coordinate points (-6, 8) and (-3, 9). The distance between the points is expressed as:
[tex]D=\sqrt{(9-8)^2+(-3-(-6))^2}\\D=\sqrt{(1)^2+(3)^2}\\D=\sqrt{10}[/tex]
Hence the distance between the two points is √10
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