The solutions to the given equation are x = -5, x = -3.
What is a quadratic equation?
An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax^2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
Quadratic equation given:
4x^2 + 32x + 60 = 0
x^2 + 8x + 15 = 0 (Dividing LHS and RHS by 4)
x^2 + 5x + 3x + 15 = 0
x(x + 5) + 3(x + 5) = 0
(x + 5)(x + 3) = 0
x = -5, x = -3
Hence, the solutions of the equation are x = -5, x = -3.
Learn more about quadratic equations on:
https://brainly.com/question/1214333
#SPJ2
