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a bin contains 78 light bulbs of which four are defective. If five are randomly selected from the bin without replacement, find the probability that all five are not defective.

Respuesta :

TaeKwonDoIsDead

Answer:

0.7630

Step-by-step explanation:

Probaility of defective = 4/78

Probability of NOT defective = 1 - 4/78 = 74/78

Note: probability of NOT A = 1 - probability of A

Since without replacement, we need to consider that with each turn, 1 goes down from total and we multiply all the 5 outcomes, hence:

Probability 5 not defective = [tex]\frac{74}{78}*\frac{73}{77}*\frac{72}{76}*\frac{71}{75}*\frac{70}{74}=0.7630[/tex]

THis is the answer, 0.7630

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