Give the number of atoms of the specified element in a formula unit of each of the following compounds, and calculate the molecular (formula) mass: (a) Oxygen in aluminum sulfate. A12(SO4)3 (b) Hydrogen in ammonium hydrogen phosphate, (NH4)2HPO4 (c) Oxygen in the mineral azurite, Cu3(OH)2(CO3)2

Respuesta :

Answer:

For a: The number of oxygen atoms in given compound is [tex]7.2264\times 10^{24}[/tex] and molecular mass of the compound is 342 g.

For b: The number of hydrogen atoms in given compound is [tex]5.4198\times 10^{24}[/tex] and molecular mass of the compound is 132 g.

For c: The number of hydrogen atoms in given compound is [tex]4.8176\times 10^{24}[/tex] and molecular mass of the compound is 344.5 g

Explanation:

Formula units is defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is [tex]6.022\times 10^{23}[/tex]

Molecular mass is defined as the sum of atomic weights of all the atoms present in the molecular formula.

  • For a:

We are given a chemical compound having formula of [tex]Al_2(SO_4)_3[/tex]

In 1 mole of aluminium sulfate, 2 moles of aluminium atoms, 3 moles of sulfur atoms and 12 moles of oxygen atoms are present.

So, number of atoms of oxygen in 1 formula unit of the compound = [tex]12\times 6.022\times 10^{23}=7.2264\times 10^{24}[/tex]

Molecular mass of aluminium sulfate = [tex][(27\times 2)+3(32+(4\times 16))]=342g[/tex]

Hence, the number of oxygen atoms in given compound is [tex]7.2264\times 10^{24}[/tex] and molecular mass of the compound is 342 g.

  • For b:

We are given a chemical compound having formula of [tex](NH_4)_2HPO_4[/tex]

In 1 mole of ammonium hydrogen phosphate, 2 moles of nitrogen atoms, 9 moles of hydrogen atoms, 1 mole of phosphorus atom and 4 moles of oxygen atoms are present.

So, number of atoms of hydrogen in 1 formula unit of the compound = [tex]9\times 6.022\times 10^{23}=5.4198\times 10^{24}[/tex]

Molecular mass of ammonium hydrogen phosphate = [tex][2(14+(4\times 1)+(1+31+(4\times 16))]=132g[/tex]

Hence, the number of hydrogen atoms in given compound is [tex]5.4198\times 10^{24}[/tex] and molecular mass of the compound is 132 g.

  • For c:

We are given a chemical compound having formula of [tex]Cu_3(OH)_2(CO_3)_2[/tex]

In 1 mole of azurite, 3 moles of copper atoms, 2 moles of hydrogen atoms, 2 mole of carbon atom and 8 moles of oxygen atoms are present.

So, number of atoms of oxygen in 1 formula unit of the compound = [tex]8\times 6.022\times 10^{23}=4.8176\times 10^{24}[/tex]

Molecular mass of azurite = [tex][(3\times 63.5)+2(16+1)+2(12+(3\times 16))]=344.5g[/tex]

Hence, the number of hydrogen atoms in given compound is [tex]4.8176\times 10^{24}[/tex] and molecular mass of the compound is 344.5 g