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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.01 mol of acetic acid. What molarity of sodium acetate will you need to add to the solution? The pKa of acetic acid is 4.74. Show all calculations in your answer

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Answer:

Explanation:

pH = p Ka + log (conjugate base / acid)

5.27 = 4.74 + log base / .01

0.53 =  + log base /.01

0.53 = log base/.01

3.38844 =   base/.01

conjugate base = .0338844 M.

Required molarity of sodium acetate is .0338844 M

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