Explanation:
The given reaction will be as follows.
[tex]CO + 2H_{2} \leftrightharpoons CH_{3}OH[/tex]
So, equilibrium constant for this equation will be as follows.
[tex]K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}[/tex]
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
[tex]K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}[/tex]
= [tex]\frac{2.4}{2.4 \times (2.4)^{2}}[/tex]
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
