which description of the graph of y= ax^2+ bx + c is not possible?

a. there are 2 x intercepts, the vertex below the x-axis, and a >0.

b. there is 1 x-int and the vertex is o. the x axis

c. there are 2 x int the vertex below is the x axis and a <0.

d. there is no x int, the vertex is above the x axis and a > 0.​

Respuesta :

The given equation: y= ax^2+ bx + c is a quadratic function.

All quadratic functions make a U shaped graph.

If a < 0 , the parabola would open downward ( an upside down U).

If the vertex is below the X axis, then there couldn't be any x intercepts.

The answer is C.