Respuesta :
Answer:
The ionization energy (in kJ/mol) of the helium ion is 21,004.73 kJ/mol .
Explanation:
[tex]E_n = -(2.18 10-18 J)\times \frac{Z^2}{n^2}[/tex]
Z = atomic mass
n = principal quantum number
Energy of the electron in n=1,
[tex]E_1= -(2.18 10^{-18} J)\times \frac{4^2}{1^2}=-3.488\times 10^{-17} J[/tex]
Energy of the electron in n = ∞
[tex]E_{\infty}= -(2.18 10^{-18} J)\times \frac{2^2}{\infty ^2}=0 J[/tex]
Ionization energy of the [tex]He^+[/tex] ion:
[tex]I.E=E_{infty}-E_1=0-(-3.488\times 10^{-17} J)=3.488\times 10^{-17} J[/tex]
[tex]I.E=3.488\times 10^{-20} kJ [/tex]
To convert in into kj/mol multiply it with [tex]N_A=6.022\times 10^{23} mol^{-1}[/tex]
[tex]I.E=3.488\times 10^{-20} kJ\times 6.022\times 10^{23} mol^{-1}=21,004.73kJ/mol [/tex]
