What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K? The latent heat of vaporization of water is 2.25 x 10^6 J kg-1.

Respuesta :

Answer : The mass of a sample of water is, 888.89 grams

Explanation :

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Formula used :

[tex]q=L\times m[/tex]

where,

q = heat = 2000 kJ = [tex]2\times 10^6J[/tex]       (1 kJ = 1000 J)

L = latent heat of vaporization of water = [tex]2.25\times 10^6J/kg[/tex]

m = mass of sample of water = ?

Now put all the given values in the above formula, we get:

[tex]2\times 10^6J=(2.25\times 10^6J/kg)\times m[/tex]

[tex]m=0.88889kg=888.89g[/tex]       (1 kg = 1000 g)

Therefore, the mass of a sample of water is, 888.89 grams

Answer:

0.88

Explanation: