Respuesta :
Answer : The mass of [tex]PbSO_4[/tex] needed are, 1.515 grams.
Explanation :
First we have to calculate the mole of [tex]PbCrO_4[/tex].
[tex]\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole[/tex]
Now we have to calculate the moles of [tex]PbSO_4[/tex].
The balanced chemical reaction will be,
[tex]PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]
From the balanced chemical reaction, we conclude that
As, 1 mole of [tex]PbCrO_4[/tex] produced from 1 mole of [tex]PbSO_4[/tex]
So, 0.005 mole of [tex]PbCrO_4[/tex] produced from 0.005 mole of [tex]PbSO_4[/tex]
Now we have to calculate the mass of [tex]PbSO_4[/tex]
[tex]\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4[/tex]
[tex]\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g[/tex]
Therefore, the mass of [tex]PbSO_4[/tex] needed are, 1.515 grams.
