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At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less than that of air. In a buoyancy experiment with a new plastic, a chemist creates a rigid, thin-walled ball that weighs 0.12 g and has a volume of 560 cm3.
(a) Will the ball float if it is evacuated?
(b) Will it float if filled with carbon dioxide (d = Lan gfL)?
(c) Will it float if filled with hydrogen (d= 0_0899 g/L)?
(d) Will it float if filled with oxygen (d = 1.330 g{ L)?
(e) Will it float if filled with nitrogen (d= 1.165 g/L)?
(f) For any case that will float, how much weight must be added to make the ball sink?

Respuesta :

Explanation:

[tex]Density =\frac{Mass}[Volume}[/tex]

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball =[tex]V=560 cm^3=560 ml=0.560 L[/tex]

[tex]D =\frac{0.12 g}{0.560 L}=0.214 g/L[/tex]

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = [tex]d_1=1.830 g/L[/tex]

Mass of the carbon dioxide gas :

[tex]1.830 g/L\times 0.560 L=1.0248 g[/tex]

Total density of filled ball with carbon dioxide gas:

[tex]\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L[/tex]

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = [tex]d_2=0.0899 g/L[/tex]

Mass of the hydrogen gas :

[tex]1.830 g/L\times 0.560 L=0.050344 g[/tex]

Total density of filled ball with hydrogen gas:

[tex]\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L[/tex]

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = [tex]d_3=1.330 g/L[/tex]

Mass of the oxygen gas :

[tex]1.330 g/L\times 0.560 L=1.7448 g[/tex]

Total density of filled ball with oxygen gas:

[tex]\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L[/tex]

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = [tex]d_4=1.165 g/L[/tex]

Mass of the nitrogen gas :

[tex]1.165 g/L\times 0.560 L=0.6524 g[/tex]

Total density of filled ball with nitrogen gas:

[tex]\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L[/tex]

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

[tex]\frac{0.12g +m}{0.560L}>1.189 g/L[/tex]

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

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