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What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 24 cm away? Your answer should be a number with two decimal places. Hint: you need to first determine the focal distance of the lens.

Respuesta :

Answer:

magnification is 0.51

Explanation:

given data

power = –4.00 D

distance d = 24 cm

to find out

What magnification

solution

first we calculate the focal length that is = 100/Power

so focal length f = 100/-4.00 = -25 cm

now calculate the image distance u that is

1/f = 1/d + 1/u

put all these value

u = fd / d - f

u = -25 ( 24) / 24 + 25

u  = 600 / 49 = -12.24 cm

image distance = - 12.24 cm

so magnification = - image distance / distance

magnification = 12.24 / 24  = 0.51

so magnification is 0.51

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