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A beam of light in air is incident on the surface of a rectangular block of clear plastic (n = 1.44 ). If the velocity of the beam before it enters the plastic is 3.00 · 108 m/s, what is its velocity inside the block?

Respuesta :

praizetk

Answer:

using this formula

n = V1/V2 ( you make V2 subject )

it becomes:

V2 = V1/n ( put in your values and cal.)

Explanation:

refractive index

= velocity in first medium / velocity in the second medium

NB : there's other ways to find refractive index, depending on the values you were given

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