Respuesta :
Answer:
The magnitude and direction of the magnetic field is 0.009014 T in the negative y direction.
Explanation:
Given that,
Speed [tex]v = 2.20\times10^7\ m/s[/tex]
Acceleration [tex]a=1.90\times10^{13}\ m/s^2[/tex]
We need to calculate the magnetic field
Using formula of magnetic field
[tex]F=qvB[/tex]....(I)
Using newton's second law
[tex] F= ma[/tex]....(II)
From equation (I) and (II)
[tex]ma=qvB[/tex]
Put the value into the formula
[tex]1.90\times10^{13}\times1.67\times10^{-27}=1.6\times10^{-19}\times2.20\times10^{7}\timesB[/tex]
[tex]3.173\times10^{-14}=1.6\times10^{-19}\times2.20\times10^{7}\timesB[/tex]
[tex]B=\dfrac{3.173\times10^{-14}}{1.6\times10^{-19}\times2.20\times10^{7}}[/tex]
[tex]B=0.009014\ T[/tex]
We need to calculate the direction of the field
Using the right hand rule, point the right hand fingers along the velocity which is in the positive z direction.
Now, if we curl the fingers along the direction of magnetic field that is in the negative y direction, then the thumb will point in the positive x direction.
Hence, The magnitude and direction of the magnetic field is 0.009014 T in the negative y direction.
