Answer:
The number of active sites enzyme have is 1.
Explanation:
Mass of penicillinase = 4.10 μg =[tex]4.10\times 10^{-6} g[/tex]
1 g = 1000000 μg
The turnover number of the enzyme at 28 °C = [tex]2.00\times 10^3 s^{-1}[/tex]
Moles of penicillinase =
[tex]\frac{4.10\times 10^{-6} g}{31200 g/mol}=1.31410\times 10^{-10} mol[/tex]
Mass of antiboitic-amoxicillin =2.83 mg =[tex]2.83\times 10^{-3} g[/tex]
Moles of amoxicillin =
[tex]\frac{2.83\times 10^{-3} g}{364 g/mol}=7.7747\times 10^{-6} mol[/tex]
Moles of reactant which are converted into product per second:
[tex]1.31410\times 10^{-10} mol\times 2.00\times 10^3 s^{-1}[/tex]
=[tex]2.6282\times 10^{-7} mol/s[/tex]
Moles of product converted in 29.6 seconds:
[tex]2.6282\times 10^{-7} mol/s\times 29.6 s=7.779472\times 10^{-6} mol[/tex]
Number of sites:
[tex]=\frac{\text{moles of product}}{\text{moles of reactant}}[/tex]
[tex]=\frac{7.779472\times 10^{-6} mol}{7.7747\times 10^{-6} mol}=1.00[/tex]
