Answer:
Step-by-step explanation:
Given that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0◦C and a standard deviation of 1◦C.
When a single thermometer is randomly selected we have the temperature is
N(0,1)
To find 48th percentile
If 48th percentile is c
then f(x<c) = 0.48 where x is the temperature of thermometer
c = 0.05
Hence we have P48 is 0.05