Answer: 0.5625
Step-by-step explanation:
Given : The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 minutes.
The density function for uniform distribution :-
[tex]f(x)=\dfrac{1}{8-0}=\dfrac{1}{8}[/tex]
The required interval : (3.25,8)=8-3.5=4.5
The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is given by :-
[tex]=\dfrac{4.5}{3.25}=0.5625[/tex]
Hence, the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes
