Answer:
[tex]2.539\times 10^{8}[/tex] helium atoms will be needed to cover 1 inch distance.
Explanation:
Diameter of helium atom = [tex]1\times 10^2 pm[/tex]
[tex] 1 pm=10^{-12} m[/tex]
1 m = 39.3701 inch
Then in [tex]10^{-12} m=10^{-12}\times 39.3701 inch[/tex]
[tex]1 pm=10^{-12}\times 39.3701 inch[/tex]
Diameter of helium atom in inches = [tex]10^2\times 10^{-12}\times 39.3701 inch[/tex]
Let the number of helium atoms required to cover 1 inch distance be x.
Total distance = 1 inch
[tex]x\times 10^2\times 10^{-12}\times 39.3701 inch=1 inch[/tex]
[tex]x=\frac{1 inch}{10^2\times 10^{-12}\times 39.3701 inch}[/tex]
[tex]x=2.539\times 10^{8}[/tex] helium atoms
[tex]2.539\times 10^{8}[/tex] helium atoms will be needed to cover 1 inch distance.
