Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added together, the y term is eliminated?
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Answer:
18 times the first equation and 8 times the second equation
Step-by-step explanation:
we have
[tex]\frac{1}{4}x-\frac{1}{6}y=5[/tex] ------> first equation
[tex]\frac{4}{5}x+\frac{3}{8}y=10[/tex] ------> second equation
step 1
Multiply the second equation by 8 both sides to remove the fraction in the variable y
[tex]8(\frac{4}{5}x+\frac{3}{8}y)=10(8)[/tex]
[tex]\frac{32}{5}x+3y=80[/tex]
step 2
Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y
[tex]18(\frac{1}{4}x-\frac{1}{6}y)=5(18)[/tex]
[tex]\frac{18}{4}x-3y=90[/tex]
step 3
Adds the new equation 1 and equation 2
[tex]\frac{18}{4}x-3y=90\\\\ \frac{32}{5}x+3y=80\\ -------[/tex]
The y-term is eliminated
therefore
The answer is
18 times the first equation and 8 times the second equation
Answer:
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added together, the x term is eliminated?
1/5x + 3/4y = 9
2/3x - 5/6y = 8
Choice A: –10 times the first equation and 3 times the second equation
Choice B: 10 times the first equation and 3 times the second equation
Choice C: –3 times the first equation and 5 times the second equation
Choice D: 3 times the first equation and 5 times the second equation
The answer is B Mark thanks and brainliest.