Answer:
width of first and second minima is = 1.022 *10^{-3} m
Explanation:
given details:
slit width =[/ex] \alpha = 0.59*10^{-9} m[/tex]
[tex]\lambda = 474 *10^{-3} m[/tex]
distance between slit and screen =130 cm =1.30m
we know
silt distance between minima = width of the maximum
[tex]\alpha *sin \theta = m\lambda[/tex]
distance between minima from central maxima is
[tex]y_m = L tan\theta[/tex]
[tex]= L sin\theta[/tex]
[tex]= m \frac{\lambda L}{\alpha}[/tex]
distance between the successive minima is given as
[tex]\Delta y =y_(m+1) - y_m[/tex]
[tex]= (m+1) \frac{\lambda L}{\alpha} - m \frac{\lambda L}{\alpha}[/tex]
[tex]= 1 m \frac{\lambda L}{\alpha}[/tex]
[tex]= \frac{ 474 *10^{-9}*1.30}{ 0.59*10^{-3}}[/tex]
= 1.022 *10^{-3} m
