Answer:
The mass of silicon in kilograms in Earth's crust is[tex]7.2729\times 10^{21} kg[/tex].
Explanation:
Mass of Earth =[tex]5.9\times 10^{21} tons[/tex]
(1 ton= 2000 lb)
(1 lb =453.6 g)
1 ton = 2000 × 453.6 g =907,200 g
Mass of Earth =[tex]5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g[/tex]
Percentage of earth crust = 0.50%
Mass of earth crust = M
[tex]0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100[/tex]
[tex]M=2.6762\times 10^{25} g[/tex]
Percentage of the silicon in Earth's crust = 27.2 %
Mass of silicon in in Earth's crust = m
[tex]Si\%=\frac{m}{M}\times 100[/tex]
[tex]27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100[/tex]
[tex]m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg[/tex]
1000 g = 1 kg
The mass of silicon in kilograms in Earth's crust is[tex]7.2729\times 10^{21} kg[/tex].