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musiclover10045

6b < 36 or 2b + 12 > 6.

Solve each side first:

6b < 36

Divide both sides by 6:

b > 36/6

b > 6

2b+12 >6

Subtract 12 from both sides:

2b >-6

Divide both sides by 2:

b < -6/2

b , -3

Rewrite as b < 6 or b > −3

JeanaShupp

Answer: [tex]b < 6\text{ or }b > -3[/tex]

Step-by-step explanation:

Given compound inequality : [tex]6b < 36\text{ or }2b + 12 > 6[/tex]

To solve the first inequality , we divide 6 on both sides, we get

[tex]b<6[/tex]

To solve the second inequality , we divide 2 on both sides, we get

[tex]b+6>3[/tex]

Now, subtract 6 on both  sides, we get

[tex]b>3-6[/tex]

i.e. [tex]b>-3[/tex]

Now, the solution of the given compound inequality :-

[tex]b < 6\text{ or }b > -3[/tex]

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