The standard molar entropy for Br2(g) is 245.46 J/(mol·K) at 25°C. Given that ΔS° = 104.58 J/K for the dissociation of one mole of Br2(g) into Br(g) at 25°C, find the standard molar entropy for Br(g) at 25°C. Enter your answer with two decimal places and no units.

Respuesta :

Answer:

The standard molar entropy for Br(g) at 25°C is 175.02J/K mol.

Explanation:

[tex]Br_2(g)\rightarrow 2Br(g),\Delta S^o=104.58 J/K [/tex]

[tex]\Delta S^{o}_{m,Br_2}=245.46 J/(mol/K)[/tex]

[tex]\Delta S^o=2 mol\times \Delta S^{o}_{m,Br} - 1 mol\times\Delta S^{o}_{m,Br_2}[/tex]

[tex]\Delta S^o= \sum \Delta S^{o}_{Products}-\sum \Delta S^{o}_{reactants}[/tex]

[tex]104.58 J/K=2 mol\times \Delta S^{o}_{m,Br} -1 mol\times 245.46 J/(mol/K)[/tex]

[tex]2 mol\times \Delta S^{o}_{m,Br}=350.04J/K[/tex]

[tex]\Delta S^{o}_{m,Br}=175.02J/K mol[/tex]

The standard molar entropy for Br(g) at 25°C is 175.02J/K mol.