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A 50. - kg pole vaulter running at 10. m/s vaults over the bar. Her speed when she is above the bar is 1.0 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.

Respuesta :

Answer:

h = 5.05 m

Explanation:

Since there is no energy loss of any kind so here we can use energy conservation

initial kinetic energy = final kinetic energy + final potential energy

[tex]\frac{1}{2}mv_i^2 = \frac{1}{2}mv_f^2 + mgh[/tex]

here we know that

[tex]v_i = 10 m/s[/tex]

[tex]v_f = 1.0 m/s[/tex]

m = 50 kg

now we have

[tex]\frac{1}{2}(50)10^2 = \frac{1}{2}(50)1^2 + 50(9.81)h[/tex]

[tex]2500 = 25 + 490.5h[/tex]

[tex]h = 5.05 m[/tex]

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