Respuesta :
Answer:
Efficiency of this process is 30 %.
Explanation:
It is given that,
Electric energy used by the machine, [tex]W_{in}=1000\ J[/tex]
The potential energy of the machine is increased, [tex]W_{out}=300\ J[/tex]
The efficiency of this machine is given by :
[tex]\eta=\dfrac{W_{out}}{W_{in}}\times 100[/tex]
[tex]\eta=\dfrac{300}{1000}\times 100[/tex]
[tex]eta=30\%[/tex]
So, the efficiency of this process is 30 %. Hence, this is the required solution.
Answer
30 %
Explanation:
Here machine uses 1000 J means input of machine is 1000 J
And its increases the potential energy by 300 J so output of the machine is 300 J
The efficiency of any system is defined as the ratio of output and input
So efficiency will be [tex]\eta =\frac{output}{input}=\frac{300}{1000}=0.3[/tex] = 30% so the efficiency of the machine will be 30%
