Answer:
Boiling point of gold is 1630 [tex]^{0}\textrm{F}[/tex] or 3239.15 K
Explanation:
We know, [tex]T(^{0}\textrm{F})=1.8T(^{0}\textrm{C})+32[/tex]
Here [tex]T(^{0}\textrm{C})[/tex] and [tex]T(^{0}\textrm{F})[/tex] are temperature in degree centigrate and temperature in degree farhenite respectively.
So, [tex]2966^{0}\textrm{C}=\frac{2966-32}{1.8}^{0}\textrm{F}[/tex]
= 1630 [tex]^{0}\textrm{F}[/tex]
We know, [tex]1^{0}\textrm{C}=273.15 K[/tex]
So, 2966 [tex]^{0}\textrm{C}[/tex] = (2966+273.15) K = 3239.15 K
