For this case we have a function of the form [tex]y = f (x).[/tex] Where:
[tex]f (x)=\frac {3 + x}{x-3}[/tex]
We must find the value of the function when [tex]x = a + 2[/tex]
So, substituting the value of "x" we have:
[tex]f (a + 2) = \frac {3+ (a + 2)} {(a + 2) -3}[/tex]
[tex]f (a + 2) = \frac {3 + a + 2} {a + 2-3}[/tex]
[tex]f (a + 2)=\frac {5 + a} {a-1}\\[/tex]
Answer:
[tex]f(a + 2) =\frac {5 + a} {a-1}[/tex]
Option C
