Make the conversion indicated ineach of the following:
(a) The length of a soccer field, 120 m (three significant figures), to feet
(b) the height of Mt. Kilimanjaro, at 19,565 ft the highest mountain in Africa, to kilometers
(c) the area of an 8.5 t 11-inche sheet of paper in cm2
(d) the displacement volume of an automobile engine, 161 in 3, to liters
(e) the estimated mass of the atmosphere, 5.6 t 1015 tons, to kilograms
(f) the mass of a bushel of rye,32.0 Ib, to kilograms
(g) the mass of a 5.00-grain aspirin tablet to miligrams(1 grain = 0.00229 oz)

Respuesta :

Explanation:

(a) The length of a soccer field, 120 m (three significant figures), to feet.

1 m = 3.28084 feet

[tex] 120 m=120\times 3.3 feet=396 feet[/tex]

(b) The height of Mt. Kilimanjaro, at 19,565 ft the highest mountain in Africa, to kilometers

1 feet = 0.0003048 km

[tex]19,565 feet=19,565\times 0.0003048 km=5.963412 km[/tex]

(c) The area of an 8.5 ×11-inche sheet of paper in [tex]cm^2[/tex].

Area of the sheet = 8.5 inches × 11 inches = 93.5 [tex]inches^2[/tex]

[tex]1 inch = 2.54 cm[/tex]

[tex]93.5 inches^{2}=93.5\times (2.54)^2 cm^2=603.2246 cm^2[/tex]

(d) The displacement volume of an automobile engine, 161 [tex]inch^3[/tex], to liters.

[tex]1 inch^3 = 0.0163871 L[/tex]

[tex]161 inch^3=161\times 0.0163871 L=2.63832 L[/tex]

(e) The estimated mass of the atmosphere, [tex]5.6\times 10^{15} tons[/tex], to kilograms.

1 ton = 907.185 kg

[tex]5.6\times 10^{15} tons=5.6\times 10^{15}\times 907.185 kg[/tex]

[tex]=5.08023\times 10^{18} kg[/tex]

(f) The mass of a bushel of rye,32.0 Ib, to kilograms

1 lb = 0.453592 kg

[tex]32.0 lb =32.0\times 0.453592 kg=14.515 kg[/tex]

(g) The mass of a 5.00-grain aspirin tablet to milligrams.

(1 grain = 0.00229 oz)

Mass of 5 grains = 5 × 0.00229 oz = 0.01145 oz

1 oz = 28349.5 mg

[tex]0.01145 oz=0.01145\times 28349.5 mg=324.601775 mg[/tex]