a. Given : Sample size : n= 1078
The number of adults said it was a good thing= 659
Then , the proportion of success : [tex]p=\dfrac{659}{1078}\approx0.611[/tex]
b. The conditions to determine whether you can apply the CLT to find a confidence interval are :-
Since the given data satisfies all the above conditions , so we can apply the CLT to find a confidence interval.
c. Given : Significance level : [tex]1-0.95=0.05[/tex]
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
The confidence interval for population proportion is given by :-
[tex]p\ \pm\ z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.611\pm (1.96)\sqrt{\dfrac{(0.611)(1-0.611)}{1078}}\approx0.611\pm0.029\\\\=(0.611-0.029,0.611+0.029)\\\\=(0.582, 0.64)[/tex]
Hence, a 95% confidence interval for the proportion who believe immigration is a good thing is (0.582, 0.64).