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What are the vertex and x-intercepts of the graph of the function below?
y= x^2 - 6x-7
A. Vertex: (3,-16); Intercepts: x = 1, -7
B. Vertex: (3, -16); Intercepts: x=-1,7
C. Vertex: (3,-2); Intercepts: x= -1,7
D. Vertex: (3,-2); Intercepts: x = 1, -7​

Respuesta :

abidemiokin

The vertex and intercept are Vertex: (3, -16); Intercepts: x=-1,7

Vertex and intercept of a line

A quadratic function is a function that has a leading degree of 2. Given the function;

y= x^2 - 6x-7

Write in vertex form

y= x^2 - 6x-7

y= x^2 - 6x + (-3)^2 -7 - (-3)^2

y = x^2 - 6x + 9 -7 - 9

y = (x-3)^2-16

Hence the vertex of the function is (3, -16)

If the value of y = 0

(x-3)^2-16 = 0

(x-3)^2 = 16

x - 3 = ±4

x = 4 + 3 and -4 + 3

x = 7 and. -1

Hence the x-intercepts of the graph are -1 and 7

Learn more on vertex here: https://brainly.com/question/525947

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