What is the sum of the probability of drawing a green marble and the probability of not drawing a green marble?

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SimplySnowy SimplySnowy · Answer 1 · 2019-08-11T05:40:31+02:00

There are a total of 6 green marbles.

Along with 3 blue and 3 red.

There is a total of 12 marbles in the bag.

This would mean that you would have 6/12 chance of getting a green marble.

If you simplify this then it would be 1/2 chance of getting a green marble.

3/12 and 3/12 chance of getting a blue or red marble.

Therefore, there is 1/2 a chance of drawing a green marble and 1/2 a chance of not drawing a green marble.

Hope this helps! :3

ap8997154 ap8997154 · Answer 2 · 2022-07-27T13:58:58+02:00

The sum of the probability of drawing a green marble and the probability of not drawing a green marble is 1.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

In the given bag the number of green marbles is 6, while the total number of marbles in the bag is 12.

Since the sum of all the probability of an event is 1.

Therefore, we can write the sum of the probability of drawing a green marble and the probability of not drawing a green marble as,

Probability (Drawing a green marble) + Probability (Not drawing a green marble) = 1

Learn more about Probability:

https://brainly.com/question/795909

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