Answer:
[tex]\boxed{\text{D. 962 K}}[/tex]
Explanation:
The volume and number of moles are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
[tex]\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}[/tex]
Data:
p₁ = 50 KPa; T₁ = 170 K
p₂ = 283 KPa; T₂ = ?
Calculations:
[tex]\begin{array}{rcl}\dfrac{50}{170} & = & \dfrac{283}{T_{2}}\\\\0.294 & = & \dfrac{283}{T_{2}}\\\\0.294T_{2} & = & 283\\\\T_{2} & = &\dfrac{283}{0.294}\\\\ & = &\textbf{962 K}\\\end{array}\\\text{The final temperature of the carbon dioxide is }\boxed{\textbf{962 K}}[/tex]
