Answer:
Dog 1: Eebb
Dog 2: EeBb
Dog 3: eeBb
Explanation:
Let's first analyze the offspring to know their genes
Black: ee (to be able to be black) Bb (because they told you black is dominant
Brown: ee (to be able to be brown) bb) (because is recessive)
Golden: Ee (because E is dominant to Golden) and here could be bb or Bb.
Now, we know what we are looking for: ee, Ee, Bb, and bb. Let's analyze the parents.
DOG 1: golden female
Ee and could be Bb or bb
DOG 2: golden male
Ee and could be Bb or bb
The had both color breed, so one will be bb and the other will be Bb.
DOG 3: black female
ee Bb (to be back)
So, because DOG 3 x DOG 2 had browned, we could say DOG 2 final alleles are EeBb and DOG 1 final alleles are Eebb