contestada

Jose is the water maintenance supervisor for his city. He knows the rate rainwater flows through a pipe is modeled by the equation R(x)= -0.1x^3+1.4x^2-1.5x, where R is the amount of water, in cubic feet, and X is time, in hours. Jose a developer of a new neighborhood that if she decreases the size of the pipe, the water flow will decrease. The function that models the decrease is D(x)-0.04x^3+0.5x^2+x, where D is the amount of water in cubic feet, and X is time, in hours.

Write a function, H(x), for the rate at which rainwater flows in the smaller pipe.

Please Help

Respuesta :

so the rainwater flows as R(x), and the decrease of the flow will be D(x), the new smaller pipe after the decrease will have water flowing at R(x) - D(x)

[tex]\bf \begin{cases} R(x)=-0.1x^3+1.4x^2-1.5x\\ D(x)=-0.04x^3+0.5x^2+x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R(x)}{(-0.1x^3+1.4x^2-1.5x)}-\stackrel{D(x)}{(-0.04x^3+0.5x^2+x)} \\\\\\ (-0.1x^3+1.4x^2-1.5x)+0.04x^3-0.5x^2-x \\\\\\ -0.1x^3+1.4x^2-1.5x+0.04x^3-0.5x^2-x \\\\\\ -0.10x^3+0.04x^3+1.4x^2-0.5x^2-1.5x-x\implies \stackrel{H(x)}{-0.6x^3+0.9x^2-1.6x}[/tex]

Otras preguntas