Answer:The sled slides 16.875m before rest.
Explanation:
[tex]a=\frac{F}{m} =\frac{12N}{20kg}[/tex]
a=0.6 m/s²
[tex]Vf=0=Vi-a.t[/tex]
[tex]t=\frac{Vi}{a} =t=\frac{4.5m/s}{0.6 m/s2} =t=7.5seg[/tex]
[tex]d= Vi.t - \frac{a.t^{2}}{2}[/tex]
[tex]d= 4.5 * 7.5 - \frac{0.6*7.5^{2} }{2} \\\\d=16.875m[/tex]
