Hey there!:
Aqueous ethanol contains water , sodium borohydride will react with water and decompose to give hydrogen gas :
NHB4 + 2 H2O => NaBO2 + 4 H2
thus a large excess of borohydride should be used used to take into account losses from the reaction with water , so that there is sufficient sodium borohydride left for the reduction of the chemical compound os interest .
Hope this helps!
The large amount of sodium borohydride used in the reduction of aqueous ethanol reaction reacts with the water of ethanol.
The reduction reaction has been the reaction in which the molecule gains the electron.
In the reduction reaction of ethanol and sodium borohydride, the products resulted includes borate and hydrogen gas.
The reactant ethanol has been aqueous in nature, and in order for complete reaction, the excess of sodium borohydride is added to utilize the water part of the reaction.
Learn more about sodium borohydride, here:
https://brainly.com/question/15594890
