Answer:
[tex]5x \log_{10}(x)-2 \log_{10}(x)[/tex]
(If that closed circle is an open circle, please let me know because that means something totally different)
Step-by-step explanation:
I think you are given:
[tex]f(x)=\log_{10}(x) \text{ and } g(x)=5x-2[/tex]
and that you are asked to find:
[tex]f(x) \cdot g(x)[/tex]
That operation means multiplication. (Let me know if is an open circle because that means something difference).
[tex]f(x) \cdot g(x)[/tex]
[tex](\log_{10}(x) \cdot (5x-2)[/tex]
Distribute:
[tex]\log_{10}(x)(5x)-\log_{10}(x)(2)[/tex]
Reorder a little (commutative property):
[tex]5x \log_{10}(x)-2 \log_{10}(x)[/tex]
