For this case we have the following equation:
[tex]\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0[/tex]
If we subtract both sides of the equation [tex]\sqrt [4] {2x + 8}[/tex] we have:
[tex]\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}[/tex]
To eliminate the radical we raise both sides of the equation to the fourth power:
[tex](\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4[/tex]
Answer:
Option D
