Answer:
4.79 J
Explanation:
The energy of a single photon is given by
[tex]E=hf[/tex]
where
[tex]h=6.63\cdot 10^{-34} Js[/tex] is the Planck constant
f is the frequency of the photon
Here we have
[tex]f=1.2\cdot 10^{10} Hz[/tex]
so the energy of one photon is
[tex]E_1=(6.63\cdot 10^{-34})(1.2\cdot 10^{10})=7.96\cdot 10^{-24} J[/tex]
Here we have 1 mol of photons, which contains
[tex]N=6.022\cdot 10^{23}[/tex] photons (Avogadro number). So, the total energy of this mole of photons is:
[tex]E=NE_1 = (6.022\cdot 10^{23})(7.96\cdot 10^{-24})=4.79 J[/tex]