PLZ HELP ASAP 30 POINTS!!!


A farmer in China discovers a mammal hide that contains 70% of its original amount of c-14.


N=n0e^kt


No=amount of c-14 at time t


K=0.0001


T=time in years


Find the age of the mammal hide to the nearest year.

Respuesta :

Substitute the given numbers for their letters in the equation:

N = NOe^kt

N - amount after t years

No = Original amount

K = 0.0001

t = number of years

Substitute the given numbers for their letters in the equation:

0.70 = 1 * e^-0.0001t

Take the logarithm of both sides:

log0.70 = loge^-0.0001t

-0.1549 = -0.0001t * 0.43429

t = -0.1549 / (-0.0001 * 0.43429)

t = 3566.74

Rounded to the nearest year = 3,567 years old.

The age of the mammal hide is  3,567 years old.

Calculation of the age of the mammal:

Given,

N = NOe^kt

Here

N - amount after t years

No = Original amount

K = 0.0001

t = number of years

Now

[tex]0.70 = 1 \times e^{-0.0001}t[/tex]

Now Take the logarithm of both sides:

[tex]log0.70 = loge^{-0.0001}t\\\\-0.1549 = -0.0001t \times 0.43429\\\\t = -0.1549 \div (-0.0001 \times 0.43429)[/tex]

t = 3566.74

Learn more about the age here: https://brainly.com/question/17880579