Respuesta :

Ben

[tex]\huge{\boxed{-\frac{1}{2}}}[/tex]

We can find the slope with [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are both points.

Plug in the values. [tex]\frac{1-(-3)}{-4-4}[/tex]

Simplify. [tex]\frac{1+3}{-4-4}[/tex]

Add/subtract. [tex]\frac{4}{-8}[/tex]

Simplify. [tex]\boxed{-\frac{1}{2}}[/tex]

CharlieBrown2002

Answer:

No.

The slope of the line is -1/2.

Step-by-step explanation:

I'll give you a hint, to solve slope of the line use [tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex].

[tex]\displaystyle \frac{1-(-3)}{(-4)-4}=\frac{4}{-8}=\frac{4\div4}{-8\div4}=\frac{1}{-2}=-\frac{1}{2}[/tex]

The slope of the line is -1/2, which is our answer.

I hope this helps!

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