Answer:
42.5 g
Explanation:
Calculate the mass of the soft drink given the density and volume:
355 mL × 1.04 g/mL = 369.2 g
Now calculate the mass of sucrose given the percentage:
0.115 × 369.2 g = 42.46 g
Rounded to 3 significant figures, the mass is 42.5 g.
Answer:
42.458 g of sucrose is contained in 355 mL (12 oz) of the soft drink
Explanation:
Volume of the soft drink = 355mL
Density = 1.04 g/mL
We know
Density = Mass / Volume
Rearranging the formula
Mass of soft drink = Density × volume
[tex]=1.04 g/mL \times 355mL=369.2 g[/tex]
[tex]Mass = \frac {(mass of solute)}{(mass of solution )} \times 100%[/tex]
[tex]11.5 = \frac {(mass of solute (sucrose))}{(mass of solution(soft drink) )} \times 100%[/tex]
[tex]11.5 = \frac {(mass of solute (sucrose))}{(369.2 g)} \times 100%[/tex]
So
Mass of sucrose
[tex]=\frac {(11.5 \times 369.2g)}{(100)}[/tex]
= 42.458 g is the Answer
