Turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand. Ben has sold no more than $30 worth of turkey sandwiches and veggie wraps in the first hour of business. Let x represent the number of turkey sandwiches and y represent the number of veggie wraps. The inequality represents the food sales in the first hour. If Ben has sold 4 veggie wraps, what is the maximum value of turkey sandwiches Ben could have sold? 5 6 7 10

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Answer:

The maximum number of turkey sandwiches Ben could have sold is 6.

Step-by-step explanation:

We are given that turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand.

Given the information, we are to find the maximum value of turkey sandwiches Ben could have sold.

[tex] 2 . 5 0 x + 3 . 5 0 y \leq 3 0 [/tex]

Number of veggie wraps sold (y) = 4

2.50x + 3.50(4) <   30

2.50x + 14          <   30

          - 14               -14

2.50x                   <   16

[tex]x<\frac{16}{2.50}[/tex]

[tex]x <6.4[/tex]

The maximum number of turkey sandwiches Ben could have sold is 6.

The maximum value of turkey sandwiches Ben could have sold is;

Option B; 6

Let number of turkey sandwiches be x

Let number of veggie wraps be y.

We are told that Turkey sandwiches cost $2.50 and veggie wraps cost $3.50.

Thus, for x number of Turkey sandwiches, the cost will be; 2.5x

For y number of veggie wraps, the cost will be 3.5y.

         We are told he sold no more than $30 worth of turkey sandwiches and veggie wraps in the first hour of business. Thus, inequality to represent this scenario is;

2.5x + 3.5y ≤ 30

Now, he has sold 4 veggie wraps. Thus;

2.5x + 3.5(4) ≤ 30

2.5x + 14 ≤ 30

2.5x ≤ 30 - 14

2.5x ≤ 16

x ≤ 16/2.5

x ≤ 6.4

Since the number can't be decimal, we approximate to a whole number to get; x = 6

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