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A box contains five slips of paper. Each slip has one of the number 4, 6, 7, 8, or 9 written on it and all numbers are used. The first player reaches into the box and draws two slips and adds the two numbers. If the sum is even, the player wins. If the sum is odd, the player loses.

a. What is the probability that the player wins?

b. Does the probability change if the two numbers are multiplied? Explain.

Respuesta :

simplyhannnah
a. If the player chooses 6, 4, and 8 each time, they have 3/5 chances to win.

6+4= 10

6+8= 14

8+4= 12

These are all even so as long as they get one of these combinations they will win

b. All three combinations still work when multiplied

6*4=24
6*8=48
8*4= 32

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