Explanation:
Heat = mass × specific heat × temperature change
q = m C ΔT
Given:
q = 337500 J
m = 50 kg
ΔT = 15°C
Substitute:
337500 J = (50 kg) C (15°C)
C = 450 J/kg/°C
Specific heat is usually recorded in J/g/°C or kJ/kg/°C. Converting:
C = 0.45 J/g/°C = 0.45 kJ/kg/°C