2koh+bacl2>2kcl+Ba(OH)2 what is the net ionic.I know all hydroxides are insolubles except with group 1A ,I presumed Ba(Oh)2 is aqueous.so I cant come up with a net ionic equation.

Salts containing Group 1 elements are soluble.
Salts containing halides are generally soluble, except the halides of silver, mercury(I), and lead.
All metallic hydroxides are insoluble except Group 2 from calcium down. So, BaCl₂ is soluble, and the molecular equation is

[tex]\rm 2KOH(aq)+ BaCl$_{2}$(aq) \longrightarrow \, $ 2KCl(aq) + Ba(OH)$_{2}$(aq)[/tex]

2. Ionic equation

[tex]\rm 2K$^{+}$(aq) + 2OH$^{-}$(aq)+ Ba$^{2+}$(aq) + 2Cl$^{-}$(aq) \longrightarrow \, $ 2K$^{+}$(aq)+ 2Cl$^{-}$(aq) + Ba$^{2+}$(aq) + 2OH$^{-}$(aq)[/tex]

3. Net ionic equation

[tex]\rm 2K$^{+}$(aq) + 2OH$^{-}$(aq)+ Ba$^{2+}$(aq) + 2Cl$^{-}$(aq) \longrightarrow \, $ 2K$^{+}$(aq)+ 2Cl$^{-}$(aq) + Ba$^{2+}$(aq) + 2OH$^{-}$(aq)[/tex]

Cancel all ions that appear on both sides of the reaction arrow (in boldface).

[tex]\textbf{2K$^{+}$(aq) + 2OH$^{-}$(aq) + Ba$^{2+}$(aq) + 2Cl$^{-}$(aq)}\\\longrightarrow \,\textbf{2K$^{+}$(aq)+ 2Cl$^{-}$(aq) + Ba$^{2+}$(aq) + 2OH$^{-}$(aq)}\\\text{Everything cancels. There is no net ionic equation.}\\\text{(nothing)} \longrightarrow \, \text{(nothing)}\\\text{Answer: }\boxed{\textbf{No reaction}}[/tex]