Answer:
So anyways the equation appears to be [tex]y=(x+4)^3+3[/tex].
Step-by-step explanation:
It looks like a cubic to me.
That is the parent function looks like [tex]f(x)=x^3[/tex].
I'm going to identify the transformations here by using the zero of the function I called f. So where has the point (0,0) on [tex]y=x^3[/tex] wonder to in the new graph. It appears to be (-4,3). So the graph moved left 4 units and up 3 units.
f(x+4)+3 moves the graph left 4 and up 3.
----------Other notes:
f(x-4)+3 moves the graph right 4 and up 3.
f(x+4)-3 moves the graph left 4 and down 3.
f(x-4)-3 moves the graph right 4 and down 3.
So anyways the equation appears to be [tex]y=(x+4)^3+3[/tex].
