Answer:
-3± √5
Step-by-step explanation:
It is given that,
m² + 6m = -4
Points to remember
Solution of a quadratic equation ax² + bx + c = 0
x = [-b ± v(b² - 4ac)]/2a
To find the solution of given equation
m² + 6m = -4
⇒ m² + 6m + 4 = 0
Here a = 1, b = 6 and c = 4
m = [-b ± v(b² - 4ac)]/2a
= [-6 ± √(6² - 4*1*4)]/2*1
= [-6 ± √(36 - 16)]/2
= [-6 ± √20]/2
= [-6 ± 2√5]/2
= -3± √5
