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Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y=2x^2+4x-3

Respuesta :

dhiab

Answer:

Step-by-step explanation:

write this expression : f(x) = a(x-h)²+k

when  the axis of symmetry is the line  : x =h and the vertex A(h,k)

y=2x²+4x-3

y = 2(x²+2x - 3/2)

y=2((x²+2x+1) -1 -3/2)

y = 2((x+1)² - 5/2)

y = 2(x+1)² -5.....vertex form      x= -1 the axis of symmetry  and A(-1,-5)the vertex

Answer:

The equation of the axis of symmetry is x = -1.

The  coordinates of the vertex are (-1, -5).

Step-by-step explanation:

y = 2x^2 + 4x - 3

y = 2(x^2 + 2x) - 3

y = 2[ (x + 1)^2 - 1] - 3

y = 2(x + 1)^2  - 5.

The equation of the axis of symmetry is x = -1.

The  coordinates of the vertex are (-1, -5)

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